Write the balanced chemical equation between H2SO4 and KOH in aqueous solution. This is called a neutralization reaction and will produce whater and potassium sulfate. Phases are optional.

0.650 L of 0.430 M H2SO4 is mixed with 0.600 L of 0.240 M KOH. What concentration of sulfuric acid remains after neutralization?

Answer:

H₂SO₄ (aq) + 2KOH (aq) --------> K₂SO₄ (aq)+ 2H₂O (l)

Next, calculate moles of each reactant:

0.650 L X 0.430 M H2SO4 = 0.2795 mol H2SO4

0.600 L X 0.240 M KOH = 0.144 mol KOH

Next, calculate moles of H2SO4 consumed by the KOH:

1 eq of H2SO4 reacts with 2 eq of KOH

0.144 / 2 M KOH = 0.072 M of H2SO4 would be reacted

So, remaining moles of H2SO4 = 0.2795 - 0.072 = 0.2075 mol H2SO4

This is in a total volume of 1.25 L, so the concentration of H2SO4 is:

0.2075 mol / 1.25 L = 0.166 M