A large population of ball bearings has a mean weight of 5.02 grams and a standard deviation of 0.30 grams. Find the probability that a random sample of 100 ball bearings chosen at random from this population has a combined weight between 496 and 500 grams.
question archive A large population of ball bearings has a mean weight of 5
A large population of ball bearings has a mean weight of 5
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Answer:
z1 = (4.96 - 5.02)/0.30 = -0.2
z2 = (5.00 - 5.02)/0.30 = -0.0667
Pr(4.96 ? X ? 5.00) = Pr( (4.96 - 5.02)/0.30 ? Z ? (5.00-5.02)/0.30 ) = Pr(-0.2 ? Z ? -0.0667)=
.0527
x1=496/100 and x2 =500/100
