Show the integral with the constant "adjustment" made for du, i

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Show the integral with the constant "adjustment" made for du, i.e. "Multiply by 1". The integral should still be all in terms of "x". The constant needed for "du" should be inside the integral and the constant not needed for "du" should be shown outside the integral. Note: Step 2 must be completely correct for any credit to be given for this problem. Step 3: Using the DL190FormulaSheet, state the formula number and the formula from the Basic Integration Rules that is needed here Step 4: State your final answer: Only these 4 steps should be included in your work. Do not include additional steps
Basic Integration Rules Jkf(u)du = k[f(uJdu JF(u)g(u)du Judu g(udu 1 2. + . du 3D ku + ? 3. 4. 3D ? + ? du - In/u+C n+1 ?" +C; ?+—1 ?+1 du 6. 'du 5. 7 'du = e" + C 1 +? - In a fa"du= a" 8 + C In a 10 9. sin u du cos ? du — sin u + C =-cosu C = - In|cos u4 esc u du ncscu+cot u cotu du nsin u 12 11 +C C tan u du J nu+C secu du Insec i 14 13. C u + tan 15. sec2 udu 2 16 CsC* ? du — — cot u + ? = tan u + C 18 17. csc ? cot u d? — — csc? + ? sec u tan u du = secu + C du du 1 arctan- + C 20 19 C = arcsin _ a u a a