question archive A shearing force of 50N is applied to an aluminum rod with a lengthof 10 m, a cross-sectional area of 1
A shearing force of 50N is applied to an aluminum rod with a lengthof 10 m, a cross-sectional area of 1
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A shearing force of 50N is applied to an aluminum rod with a lengthof 10 m, a cross-sectional
area of 1.0 × 10−5 m, and a shear modulus of 2.5× 1010 N/m2. As a result the rod is sheared
through a distance of:
A. zero
B. 1.9mm
C. 1.9 cm
D. 19 cm
E. 1.9m
