question archive Part A What is the magnetic field strength at point 1 in the figure? (B_1= ? T) Part B: What is the magnetic field direction at point 1 in the figure? (out of the page or into the page?) Part C: What is the magnetic field strength at point 2 in the figure? (B_2= ? T) Part D: What is the magnetic field direction at point 2 in the figure? Part E: What is the magnetic field strength at point 3 in the figure? (B_3= ? T) Part F: What is the magnetic field direction at point 3 in the figure? I'm using B= (Mu_0*I)/(2*pi*r_2) = (4*pi*10^-7)I/(2*pi*r_2) = 4*10^-7/2*r_2 and finding that B_1= (4*10^-7) (10A) / (2) (0
Part A What is the magnetic field strength at point 1 in the figure? (B_1= ? T) Part B: What is the magnetic field direction at point 1 in the figure? (out of the page or into the page?) Part C: What is the magnetic field strength at point 2 in the figure? (B_2= ? T) Part D: What is the magnetic field direction at point 2 in the figure? Part E: What is the magnetic field strength at point 3 in the figure? (B_3= ? T) Part F: What is the magnetic field direction at point 3 in the figure? I'm using B= (Mu_0*I)/(2*pi*r_2) = (4*pi*10^-7)I/(2*pi*r_2) = 4*10^-7/2*r_2 and finding that B_1= (4*10^-7) (10A) / (2) (0
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Part A What is the magnetic field strength at point 1 in the figure?
(B_1= ? T)
Part B:
What is the magnetic field direction at point 1 in the figure?
(out of the page or into the page?)
Part C:
What is the magnetic field strength at point 2 in the figure?
(B_2= ? T)
Part D:
What is the magnetic field direction at point 2 in the figure?
Part E:
What is the magnetic field strength at point 3 in the figure?
(B_3= ? T)
Part F:
What is the magnetic field direction at point 3 in the figure?
I'm using B= (Mu_0*I)/(2*pi*r_2) = (4*pi*10^-7)I/(2*pi*r_2) = 4*10^-7/2*r_2
and finding that B_1= (4*10^-7) (10A) / (2) (0.02m) = 1.0*10^-4 T
However, this answer is incorrect.
What am I doing wrong, and how do I find parts A through F?
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your B_1 seems correct but you considered only the field due to the top wire due to bottom wire you get a field in the opposite direction so subtract these two to get the field due to both fields.for example B_! is your answer - 3.3333x10^-5 = +6.666x10^-5
