How many Hydrogen atoms are contained in 28.86 g of C4H10O2N?

Answer:

mass of C₄H₁₀O₂N = 28.86 g

molar mass of C₄H₁₀O₂N = 104.1277 g/mol

no. of mole = mass of compound in g / molar mass

moles of C₄H₁₀O₂N = 28.86 g / 104.1277 = 0.27716 mol

in 1 mole of C₄H₁₀O₂N contain 10 mole of hydrogen atom then 0.27716 mole of C₄H₁₀O₂N contain mole of hydrogen atom = 0.27716 X 10 = 2.7716 mole of hydrogen atom

No. of Atoms = no. of moles X N_A

Where,

N_A = Avogadro’s number = 6.022 X 10²³

No. of H atoms moles = 2.7716 moles

Substitute the value in above equation

No. of atoms of H = 2.7716 X 6.022 X 10²³

No. of H atoms = 1.669 X 10²⁴