question archive There is a need to create a 95% confidence interval of the number of calories in chocolate chip cookies of normal size based on a sample of 9 cookies from different bakeries
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There is a need to create a 95% confidence interval of the number of calories in chocolate chip cookies of normal size based on a sample of 9 cookies from different bakeries. The sample has a mean of 75 calories and a sample standard deviation, s, of 27.3. Please Interpret the results so I could understand how to do it.
Answer
75 + or - 20.98
Upper limits = 75 + 20.98 = 95.98
Lower limits = 75 - 20.98 = 54.02
95% confidence interval = [ 54.02 , 95.98]
Interpretation
We are 95% confident that the true population mean of the number of calories in chocolate chip cookies is between 54.02 to 95.98
Step-by-step explanation
Explanation
Data
Sample size n = 9
Sample mean x? = 75
Sample standard deviation s = 27.3
A 95% confidence interval of the number of calories in chocolate chip cookies is calculated as follows;
Sample mean x? + or - 95% confidence level t critical value with n-1 degrees of freedom x Standard error
We use Student's t test since sample size n is smaller that is n< 30 and population standard deviation is unknown.
Sample mean x? = 75
95% confidence level t critical value with n-1 degrees of freedom = t0.05/2 , n-1 = t0.025, 8 = From t distribution table t critical value = 2.306
Standard error = s/?n
= 27.3/ ?9
= 27.3/3
= 9.1
95% confidence interval will be;
x? + or - 2.306 x 9.1
75 + or - 20.98
Upper limits = 75 + 20.98 = 95.98
Lower limits = 75 - 20.98 = 54.02
95% confidence interval = [ 54.02 , 95.98]
Interpretation
We are 95% confident that the true population mean of the number of calories in chocolate chip cookies is between 54.02 to 95.98