question archive It requires 1000 J of work to stretch a spring 3
It requires 1000 J of work to stretch a spring 3
Subject:PhysicsPrice:2.87 Bought7
It requires 1000 J of work to stretch a spring 3.00 cm. Which of the following is the change in potential energy and the spring constant of the spring?
a. increase in potential energy = 1.50x103 J
spring constant = 333 N/m
b. increase in potential energy = 15.0 J
spring constant = 3.33x104 N/m
c. increase in potential energy = 1000 J
spring constant = 2.22x106 N/m
d. increase in potential energy = 30.0 J
spring constant = 6.67x106 N/m
Purchase A New Answer
Custom new solution created by our subject matter experts
GET A QUOTE
Answer Preview
Answer:
W=0.5*k*(X)2
1000=.5*k*.03*.03
k=2.22*106 N/m
Now work done by all the forces=change in potential energy+change in kinetic energy
1000=U+0
since change in kinetic energy is 0
U=1000 J
