question archive If you wanted to determine how much KOH KOH (potassium hydroxide; a strong base) was dissolved in water, you could titrate it with a known amount of KHP KHP (potassium hydrogen phthalate; a weak acid) until a color change indicates that the base is completely neutralized

If you wanted to determine how much KOH KOH (potassium hydroxide; a strong base) was dissolved in water, you could titrate it with a known amount of KHP KHP (potassium hydrogen phthalate; a weak acid) until a color change indicates that the base is completely neutralized

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If you wanted to determine how much KOH

KOH (potassium hydroxide; a strong base) was dissolved in water, you could titrate it with a known amount of KHP

KHP (potassium hydrogen phthalate; a weak acid) until a color change indicates that the base is completely neutralized. The molecular equation below depicts this neutralization reaction.

 

KHP(aq)+KOH(aq)→K

2

P(aq)+H

2

O(l)

KHP(aq)+KOH(aq)→K2P(aq)+H2O(l)

Write the net ionic equation that depicts the neutralization of the base KOH

KOH by KHP

KHP. Instead of using the entire chemical formula of phthalate, use HP

HP− to represent the acidic hydrogen phthalate ion and P

2−

P2− to represent the phthalate ion.

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