Q1) For a human eye with a pupil diameter (aperture diameter D) of 0

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Q1) For a human eye with a pupil diameter (aperture diameter D) of 0.005 meters, and a focal length of 0.022 meters, there will be a resolution limit due to diffraction at 550 nm wavelength. If we space light-sensitive cells on the retina at this spacing, how many retina cells per square meter (of retina) would there need to be and why? You may assume that light-sensitive cells are spaced in a grid.

Q2) Now suppose there are giants which are exactly twice the size of humans in each dimension. So giant eyes have pupils of 0.01 meters, and a focal length of 0.044 meters. Does the spacing of light-sensitive cells change and if so, by how much?