question archive A 500N gymnast performing a giant swing with an angular velocity of 5 rad/sec, exerts 90 Nm of torque on the support bar
A 500N gymnast performing a giant swing with an angular velocity of 5 rad/sec, exerts 90 Nm of torque on the support bar
Subject:PhysicsPrice:2.86 Bought3
A 500N gymnast performing a giant swing with an angular velocity of 5 rad/sec, exerts 90 Nm of torque on the support bar. How much torque is exerted by the bar on the gymnast's hands?
The amount of torque which must by generated by the biceps brachii at the elbow in order to maintain the arm in a particular position is 50 Nm. If the biceps attaches to the radius at a perpendicular distance of 3 cm from the joint center at the elbow, how much force must the muscle produce?
A person is trying to close a door by applying a force of 87 N at a distance that is 0.50 m from the door hinge. A second person is trying to open that door by applying a force of 135 N at a distance of 0.31 m from the door hinge. What will happen?
A 30 kg child sits on the right end of a see-saw 1 m from the axis. If a 20 kg child sits on the left end of the see-saw 2 m from the axis, what will happen?
Purchase A New Answer
Custom new solution created by our subject matter experts
GET A QUOTE
Answer Preview
1) 90 N?m
2) 1667 m
3) The door will open
4) the see-saw will tilt to the left
Step-by-step explanation
1)
According to the 3rd law of Newton,
90 N?m
2)
TM = FM × AM
FM = TM/AM
= 50 Nm/0.03m
= 1666.6 = 1667 N
3)
The peron who opens the door
T = 87 x 0.50 = 43.5 N
The person who closes the door
T = 135 x 0.31 = 41.85 N
So door opens
