question archive The following table represents the addresses and contents (using hexadecimal notation) of some cells in a machine's main memory

The following table represents the addresses and contents (using hexadecimal notation) of some cells in a machine's main memory

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The following table represents the addresses and contents (using hexadecimal notation) of some cells in a machine's main memory. Starting with this memory arrangement, follow the sequence of instructions and record the final contents of each of these memory cells:
Address Contents
00 .............. AB
01 ............... 53
02 ............... D6
03 ................ 02
Step 1, Move the contents of the cell whose address is 03 to the cell at address 00.
Step 2, Move the value 01 into the cell at address 02.
Step 3, Move the value stored at address 01 into the cell at address 03.

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Record the Final Contents of Memory Cells

Let us consider the following table representing addresses and contents using hexadecimal notation of the cells in a machine's main memory:

 

Address

Contents

00

AB

01

53

02

D6

03

02

 

We have to record the final contents of the memory cells on following the sequence of instructions.

 

Sequence of instructions is as follows:

Step 1: Move the contents of the cell whose address is 03 to the cell at address 00.

Step 2: Move the value 01 into the cell at address 02.

Step 3: Move the value stored at address 01 into the cell at address 03.

On following the step 1, the content at address 00 replaces with the value at the address 03. We get the contents as shown in the following table:

 

Address

Contents

Contents after step 1

00

AB

02

01

53

53

02

D6

D6

03

02

02

 

In step 2, Move the value 01 into the cell at address 02 the contents are as follows:

 

Address

Contents

Contents after step 2

00

AB

02

01

53

53

02

D6

01

03

02

02

 

In step 3, Move the value stored at address 01 into the cell at address 03. The contents of the memory cells are:

 

Address

Contents

Contents after step 3

00

02

02

01

53

53

02

01

01

03

02

53

 

Hence, the final contents of the main memory cells after the sequence of instructions are:

 

Address

Final Contents

00

02

01

53

02

01

03

53

 

please see the attached file for the complete solution.

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