Explain how time in the air for a projectile is affected by the angle of release. For equal take off and landing height, what is the optimal angle of release to maximize time in the air?

Also indicate for a release angle of 45 degrees, how time up and time down are or are not affected by when the landing height is above, rather than equal to the take-off height. Ensure you explain your answer.

This is based on projectile motion...

Step-by-step explanation

We know that the time in air is basically dependent on vertical component of initial velocity...as we increase the launch angle, the vertical component will increase. Therefore, with increase in launch angle , the time in air will increase.

if launch and landing height is same, then maximum time in air is achieved when we launch the projectile vertically upwards means when launch angle is 90 degrees.

Now, for an angle of 45 degrees, when landing height is above the launching height, the time up in the air will be different from time downwards. Time to reach maximum height from launching point will be more than time to reach the landing height from maximum height.