question archive An ice skater performs a fast spin by pulling outstretched arms down and close to her body

An ice skater performs a fast spin by pulling outstretched arms down and close to her body

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An ice skater performs a fast spin by pulling outstretched arms down and close to her body. What happens to
her angular momentum with respect to the axis of rotation? A it decreases O B. It increases O C. It doesn't
change Q D. It depends how fast she rotates

 

 

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Option c:

It doesn't change.

Step-by-step explanation

Angular momentum is the product of angular velocity(?ω?) and moment of inertia(I)

Angular momentum = ?ω? I ------(1)

As the skater pulls her outstretched arms down and close to her body, moment of inertia( or mass distribution) decrease. It cause her to spin faster which means that the angular velocity increase.

In equation (1), ?ω? increase and I decrease. So final momentum doesn't change.

 

Option c:

The final momentum doesn't change.