question archive Two lasers are shining on a double slit, with slit separation d
Two lasers are shining on a double slit, with slit separation d
Subject:PhysicsPrice:2.85 Bought3
Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelength of d/15. The lasers produce separate interference patterns on a screen a distance 6.00 m away from the slits. Which laser has its first maximum closer to the central maximum? Ans: laser 1 What is the distance Deltaymax-max between the first maxima (on the same side of the central maximum) of the two patterns? Deltaymax-max= m What is the distance Deltaymax-min between the second maximum of laser 1 and the third minimum of laser 2, on the same side of the central maximum? Deltaymax-min = m
Purchase A New Answer
Custom new solution created by our subject matter experts
GET A QUOTE
Answer Preview
For part be we can use the equation
ym = m*λ*L/d
so for the first max for each one m =1
so for laser 1
y = (d/20)*(6.0m)/d
the d cancel out so we have
y = 6.0m /20 = 0.3
for laser 2 we do the same thing
y = 6.0m/15 = 0.4
y ( laser1 ) < y ( laser2 )
(1) hence first maxima of laser1 is closest to central maxima
Δy = 0.4m -0 .3 m = 0.1m
For part C)
we use the same equation to find the y for laser 1, except m =2
y= 2*6.0 m / 20 = 0.6 m
Now for laser 2 we use:
ym=(m+1/2)*λ*L/d
since there is no central minimum the first minimum is at m = 0.that means that the third minimum is at m = 2
simplifying the equation we get
y = (2.5)*6.0 / 15 = 1m
now we solve
Δy= 1m - 0.6m = 0.4 m
