question archive The molar solubility of Ag2SO4 in pure water is 1

The molar solubility of Ag2SO4 in pure water is 1

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The molar solubility of Ag2SO4 in pure water is 1.2x10-5 M. Calculate the Ksp.

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Answer:

Ag2SO4 <=> 2 Ag+ + SO42-

Molar solubility = [SO42-] = 1.2 x 10-5 M

[Ag+] = 2 x [SO42-] = 2 x 1.2 x 10-5 = 2.4 x 10-5 M

Ksp = [Ag+]2[SO42-]

= (2.4 x 10-5)2 x 1.2 x 10-5 = 6.9 x 10-15

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