question archive Balance the equation: ___C2O4^2- +_____H^+ +_______MnO4^- yields _____CO2 + _____Mn^2+ + ____H2O a) Mass Na2C2O4: 0

Balance the equation: ___C2O4^2- +_____H^+ +_______MnO4^- yields _____CO2 + _____Mn^2+ + ____H2O a) Mass Na2C2O4: 0

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Balance the equation:

___C2O4^2- +_____H^+ +_______MnO4^- yields _____CO2 + _____Mn^2+ + ____H2O

a) Mass Na2C2O4: 0.278 g

b) Molar mass of Na2C2O4 :

c) Moles Na2C2O4:

d) Volume of solution: 50.00 mL

e) Molarity of Na2C2O4 :

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(1)

 

5C2O42- + 16H+ + 2MnO4-—> 10CO2 + 2Mn2+ + 8H2O

 

 

(2)

a) Mass Na2C2O4: 0.278 g

b) Molar mass of Na2C2O4 : 134 g/mol

c) Moles Na2C2O4: 

0.278 grams * 1 mol/134 grams = 2.07 x 10-3 mol

d) Volume of solution: 50.00 mL

50 ml * 1L/1000 mL= 0.05 L

e) Molarity of Na2C2O4 :

 

Molarity= mol/ L

= 2.07 x 10-3 mol / 0.05L

=0.041 M

Step-by-step explanation

(1) Balance by inspection:

 

5C2O42- + 16H+ + 2MnO4-—> 10CO2 + 2Mn2+ + 8H2O

 

(2)

 

a) Mass Na2C2O4: 0.278 g

b) Molar mass of Na2C2O4 : 134 g/mol

c) Moles Na2C2O4: 

0.278 grams * 1 mol/134 grams = 2.07 x 10-3 mol

d) Volume of solution: 50.00 mL

50 ml * 1L/1000 mL= 0.05 L

e) Molarity of Na2C2O4 :

 

Molarity= mol/ L

= 2.07 x 10-3 mol / 0.05L

=0.041 M