question archive As an additional answer, if we were specifically talking about, say, ##"Br"-"Br"##, ##"F"-"F"##, etc
As an additional answer, if we were specifically talking about, say, ##"Br"-"Br"##, ##"F"-"F"##, etc
Subject:ChemistryPrice: Bought3
As an additional answer, if we were specifically talking about, say, ##"Br"-"Br"##, ##"F"-"F"##, etc., then no, those wouldn't show up.
IR-active vibrational motions, i.e. those that change the dipole moment of the molecule, show up in an IR spectrum.
So in the above diagram of ##"CO"_2##, ##B## (asymmetric stretch), ##C## (in-the-plane scissoring), and ##D## (out-of-the-paper scissoring) are IR-active, but ##A## is not because ##A## is totally symmetric; the changes in dipole moment cancel out in the horizontal directions.
Since diatomic halogens can only stretch one way, and that one way is totally symmetric, there is no change or production of a dipole moment. Thus, there are no IR-active vibrational motions possible.
Same with ##"O"_2##, ##"N"_2##, and other homonuclear diatomic species.
(Something like ##"H"-"Cl"## would show up though.)
