Seventy-five percent of employees make judgments about their co-workers based on the cleanliness of their desk. You randomly select 8 employees and ask them if they judge co-workers based on this criterion. The random variable is the number of employees who judge their co-workers by cleanliness. Which outcomes of this binomial distribution would be considered unusual?

Group of answer choices

1, 2, 3

0, 1, 2, 3, 8

0, 1, 2, 7, 8

0, 1, 2, 3

 

Answer:

0, 1, 2, 3

Explanation:

The outcome considered unusual if probability less than 0.05

Given , n = 8 , p = 0.75

First we have to find probability for each outcome of Binomial Distribution.

Using Excel function , " =BINOMDIST( x, n , p , 0 )"

P( x = 0 ) = BINOMDIST(0, 8, 0.75, 0) = 0.00002

P( x = 1 ) = BINOMDIST(1, 8, 0.75, 0) = 0.00037

P( x = 2 ) = BINOMDIST(2, 8, 0.75, 0) = 0.00385

P( x =3 ) = BINOMDIST(3, 8, 0.75, 0) = 0.02307

P( x =4 ) = BINOMDIST(4, 8, 0.75, 0) = 0.08652

P( x =5 ) = BINOMDIST(5, 8, 0.75, 0) = 0.20764

P( x =6 ) = BINOMDIST(6, 8, 0.75, 0) = 0.31146

P( x =7 ) = BINOMDIST(7, 8, 0.75, 0) = 0.26697

P( x =8 ) = BINOMDIST(8, 8, 0.75, 0) = 0.10011

The outcome 0, 1, 2, 3 has probability less than 0.05

So , these outcomes of this binomial distribution would be considered unusual.