question archive The following reaction is a single-step, bimolecular reaction: CH3Br+ NaOH rightarrow CH3OH + NaBr When the concentrations of CH3Br and NaOH are both 0
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The following reaction is a single-step, bimolecular reaction: CH3Br+ NaOH rightarrow CH3OH + NaBr When the concentrations of CH3Br and NaOH are both 0.140 M, the rate of the reaction is 0.0080 M/s. What is the rate of the reaction if the concentration of Ch3Br is doubled? M/s What is the rate of the reaction if the concentration of NaOH is halved? M/s What is the rate of the reaction if the concentrations of CH3Br and NaOH are both increased by a factor of three? M/s
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