question archive Glucose is consumed in the presence of oxygen to afford carbon dioxide and water as shown in the balanced reaction: 6O2 + C6H12O6 --> 6CO2 + 6H2O If one gram of Glucose is allowed to react with 1 gram of oxygen, which statement is correct? A
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Glucose is consumed in the presence of oxygen to afford carbon dioxide and water as shown in the balanced reaction: 6O2 + C6H12O6 --> 6CO2 + 6H2O
If one gram of Glucose is allowed to react with 1 gram of oxygen, which statement is correct?
A.water is the limiting reactant
B.carbon dioxide is the limiting reactant
C.Glucose is the limiting reactant
D.oxygen is the limiting reactant
The answer is C. Glucose is the limiting reactant
Step-by-step explanation
First step to do is to change all the given reactants from grams to moles. We do this by using the molar conversion of each compound. As shown in the solution below, where for every 32 g of Oxygen (O2) it is equivalent to 1 mol of Oxygen (O2) and for 180.06 g of Glucose (C6H12O6) it is equivalent to 1 mol of Glucose (C6H12O6).
After that, we then assume the amount of each reactant needed to fully used the amount of the other reactant to produce the reaction. For this we used the balanced equation to make the mole ratio.
Based on the equation given, the mole ratio of glucose to oxygen is 6:1 or for every 1 mole of glucose you need 6 moles of oxygen.
Now we use this mole ratio to compute the amount of each reactant needed.
For the amount of glucose needed:
For the amount of oxygen needed:
Based from this, to fully consume the given amount of glucose (C6H12O6) we need 0.0333 moles of oxygen (O2) but we are only given 0.03125 moles of oxygen which makes glucose (C6H12O6) the limiting reactant since the amount of oxygen (O2) needed to fully consume glucose is smaller than the given amount of oxygen (O2).
Please see the attached file for the complete solution