Glucose is consumed in the presence of oxygen to afford carbon dioxide and water as shown in the balanced reaction: 6O₂ + C₆H₁₂O₆ --> 6CO₂ + 6H₂O

If one gram of Glucose is allowed to react with 1 gram of oxygen, which statement is correct?

A.water is the limiting reactant

B.carbon dioxide is the limiting reactant

C.Glucose is the limiting reactant

D.oxygen is the limiting reactant

The answer is C. Glucose is the limiting reactant

Step-by-step explanation

First step to do is to change all the given reactants from grams to moles. We do this by using the molar conversion of each compound. As shown in the solution below, where for every 32 g of Oxygen (O₂) it is equivalent to 1 mol of Oxygen (O₂) and for 180.06 g of Glucose (C₆H₁₂O₆) it is equivalent to 1 mol of Glucose (C₆H₁₂O₆).

After that, we then assume the amount of each reactant needed to fully used the amount of the other reactant to produce the reaction. For this we used the balanced equation to make the mole ratio.

Based on the equation given, the mole ratio of glucose to oxygen is 6:1 or for every 1 mole of glucose you need 6 moles of oxygen.

Now we use this mole ratio to compute the amount of each reactant needed.

For the amount of glucose needed:

For the amount of oxygen needed:

Based from this, to fully consume the given amount of glucose (C₆H₁₂O₆) we need 0.0333 moles of oxygen (O₂) but we are only given 0.03125 moles of oxygen which makes glucose (C₆H₁₂O₆) the limiting reactant since the amount of oxygen (O₂) needed to fully consume glucose is smaller than the given amount of oxygen (O₂).

Please see the attached file for the complete solution