question archive Calculate the cell potential for the following reaction as written at 25

Calculate the cell potential for the following reaction as written at 25

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Calculate the cell potential for the following reaction as written at 25.00 °C, given that [Mg2 ] = 0.810 M and [Ni2 ] = 0.0170 M. Standard reduction potentials can be found here.

Mg(s) + Ni2+(aq) >< Mg2+(aq) + Ni(s)    E=

 

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Mg(s) + Ni2+(aq) <====> Mg2+(aq) + Ni(s)    

Mg(s) ---> Mg2+ + 2e-    E0 = + 2.37 V

Ni2+ + 2e- ----> Ni(s)    E0 = - 0.25 V

E0cell = 2.37 - 0.25 => 2.12 V

Ecell = E0cell - (0.059 / n) log[Q]

Ecell = 2.12 V - 0.059 / 2 log[0.810 / 0.0170]

Ecell = 2.12 - 0.049

Ecell = 2.07 V

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